SICKENING, SIRS, SICKENING AN INT TAKES THE SAME AMOUNT OF MEMORY AS A LONG!!
YOU CAN TEST IT YOURSELF !!
WARNING:THIS WILL DISGUST YOU
#include <stdio.h>
#include <stdlib.h>
int main()
{
char c;
int i;
long l;
printf( "A char is this big: %d\n", sizeof(c) );
printf( "An int is this big: %d\n", sizeof(i) );
printf( "A long is this big: %d\n", sizeof(l) );
}
Name:
Anonymous2008-02-05 9:08
You should use %u instead of %d
Name:
Anonymous2008-02-05 9:14
You should read SICP
Name:
Anonymous2008-02-05 9:21
aaaa what did you do to my computer?
Name:
Anonymous2008-02-05 9:22
Does printf support BBCode?
Name:
Anonymous2008-02-05 10:01
This is platform specific. A long can be bigger than an int
Name:
Anonymous2008-02-05 10:01
SERIOUS FUCKING DISCUSSION HERE GUYS
Name:
Anonymous2008-02-05 10:06
>>6
I'm on a Slackware derivative!! Why is this happening to me!?
Name:
Anonymous2008-02-05 10:09
I think it's more influenced by hardware. On a 32bit x86, ints are probably 32 bits. The c standard only makes a guarantee something like that short is less than long, and that int is >= short and <= long or something
Name:
Anonymous2008-02-05 10:16
<=>
Name:
Anonymous2008-02-05 10:16
When I wrote an ANSI C compiler, it had longs longer than ints.
Name:
Anonymous2008-02-05 10:36
% ./a.out
A char is this big: 1
An int is this big: 4
A long is this big: 8
whut
Use Arch Linux.
Name:
Anonymous2008-02-05 11:33
From the C90 standard:
5.2.4.5.1 Sizes of integral types <limits.h>
The values given below shall be replaced by constant expressions suitable for use in #if preprocessing directives. Moreover, except for CHAR_BIT and MB_LEN_MAX, the following shall be replaced by expressions that have the same type as would an expression that is an object of the corresponding type converted according to the integral promotions. Their implementation-defined values shall be equal or greater in magnitude (absolute value) to those shown, with the same sign.
[...]
-- minimum value for an object of type int INT_MIN -32767
-- maximum value for an object of type int INT_MIN +32767
[...]
-- minimum value for an object of type long int LONG_MIN -2147483647
-- maximum value for an object of type long int LONG_MIN +2147483647
Name:
Anonymous2008-02-05 11:34
>>13
In other words, ints are at least two bytes, longs are at least four bytes, and both can be longer than that depending on your implementation.
>>14 WRONG. ints are at least 16 bits wide, longs are at least 32 bits wide. The size of a `byte´ is given by CHAR_BIT, which is at least 8 (but can be more).
Also, sizeof does not yield an int, so %d is wrong. The correct formatting specifier is %zu.
Name:
Anonymous2008-02-05 12:45
nigger[~]$ ./sizeof
A char is this big: 1
An int is this big: 4
A short is this big: 2
A long is this big: 4
Name:
Anonymous2008-02-05 12:50
A char is this big: -3
An int is this big: |--------|
A SICP is this big: 9?2¤#@brntszfa42{%NO CARRID I CAN'T DO THAT, DADAISY, GIVE Me your aaanswrdOoooo .
Name:
Anonymous2008-02-05 13:02
GRAPHICAL FAGGOTRY
#include <stdio.h>
#include <stdlib.h>
int main()
{
int i;
i = sizeof(char);
printf( "A char is this big: |" );
while( i > 0)
{
printf( "-" );
--i;
}
printf( "|\n" );
i = sizeof(int);
printf( "An int is this big: |" );
while( i > 0)
{
printf( "-" );
--i;
}
printf( "|\n" );
i = sizeof(short);
printf( "A short is this big: |" );
while( i > 0)
{
printf( "-" );
--i;
}
printf( "|\n" );
i = sizeof(long);
printf( "A long is this big: |" );
while( i > 0)
{
printf( "-" );
--i;
}
printf( "|\n" );
return 0;
}
Name:
Anonymous2008-02-05 13:05
Use for(i = sizeof(char); i > 0; i--)
printf("-");
Name:
Anonymous2008-02-05 13:09
>>19
Good Sir, I say, graphicalities are the least of your faggotry.
>>32
no shit, the size of char is always 1.
Did yo,u think this much faggot? are you sure you weren't trying to say 'types/objects in C have to have positive sizes?'
>>53
YEAH, you did well there
tell him how much that fag fails and then SAGE THE THREAD TO DEATH
you really did show him, i admire you, i think you are my internet superhero.
Name:
Anonymous2008-02-05 21:51
improved guifications
c.patch
10,11c10,11
< printf( "A char is this big: |" );
< while( i > 0)
--- printf( "A char is this big: 8" ); while( i > 0)
13c13
< printf( "-" );
--- printf( "=" );
15,16c15,16
< }
< printf( "|\n" );
--- } printf( "D\n" );
20c20
< printf( "An int is this big: |" );
--- printf( "An int is this big: 8" );
23c23
< printf( "-" );
--- printf( "=" );
26c26
< printf( "|\n" );
--- printf( "D\n" );
30c30
< printf( "A short is this big: |" );
--- printf( "A short is this big: 8" );
33c33
< printf( "-" );
--- printf( "=" );
36c36
< printf( "|\n" );
--- printf( "D\n" );
40c40
< printf( "A long is this big: |" );
--- printf( "A long is this big: 8" );
43c43
< printf( "-" );
--- printf( "=" );
46c46
< printf( "|\n" );
--- printf( "D\n" );
Name:
Anonymous2008-02-05 21:53
b.c
#include <stdio.h>
#include <stdlib.h>
int main()
{
int i;
i = sizeof(char);
printf( "A char is this big: 8" );
while( i > 0)
{
printf( "=" );
--i;
}
printf( "D\n" );
i = sizeof(int);
printf( "An int is this big: 8" );
while( i > 0)
{
printf( "=" );
--i;
}
printf( "D\n" );
i = sizeof(short);
printf( "A short is this big: 8" );
while( i > 0)
{
printf( "=" );
--i;
}
printf( "D\n" );
i = sizeof(long);
printf( "A long is this big: 8" );
while( i > 0)
{
printf( "=" );
--i;
}
printf( "D\n" );
>>55,56
A char can have 8 bits or more.
check CHAR_BIT
Name:
Anonymous2008-02-05 22:35
A char is this big: 1
An int is this big: 4
A long is this big: 8
Hmm.
Name:
Anonymous2008-02-06 4:35
>>57
Your point being what? CHAR_BIT only says how many bits are in a char. It's still one byte.
Or to put it differently, since perhaps if I use some BBCode it'll sink in: The number of bits in a byte (#defineCHAR_BIT) is entirely independent of the number of bytes in a char(which is ALWAYS one).
Name:
Anonymous2008-02-06 4:58
>>59
Indeed, section 3.5 of the C90 standard states defines a character as "a bit representation that fits in a byte"
PROTIP: int and long size vary on different platforms
Name:
Anonymous2009-03-06 12:46
2 y1 y2 z1?
Name:
Anonymous2009-07-12 6:16
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