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(Java) Method to check for primeness

Name: Anonymous 2006-11-06 21:52

So let's suppose I have an array of 100 integers.

I want to take each integer in the array (primes[i]) and send it to a boolean method. The method is supposed to take the integer and see if it's prime or not and return true or false to main. In main, I'm supposed to display the prime integers and also show the entire array via println. Here's what I have, how do I fix?

public static void main(String[] args)
    {
     int[] primes = new int[100];
     for(int i=0; i<primes.length; i++)
     {
      double k=(1+Math.random()*100);
      primes[i]=(int)k;
      System.out.println(primes[i]);
      isprime(primes[i]);
     }
    }
public static boolean isprime(int x)
    {                     
        for (int test = 2; test <= x; test++) 
        {
            if (x % test == 0)
            {
             
            }
        }   
    }
}

Name: Anonymous 2006-11-06 22:34

omg test for 1.

Name: Anonymous 2006-11-06 23:12

If you're checking numbers in increments (Not random, like yours), you could simply make an array(list if you're lazy and willing to sacrifice some speed) and use that to store prime numbers. Then to check whether say, x, is a prime number is not, you only need to divide by the modulus of all the primes between 0 and sqrt(x).

Name: Anonymous 2006-11-07 6:44

>>1
Use Python lol
No need for arrays
Check n to divide from 2 to floor(sqrt(n))
More information here: http://python.org

Name: Anonymous 2006-11-07 13:07

>>4
perl > python

sub is_prime{
 map{return 0 if not $n%$_}2..int sqrt($n=pop);
 return $n<2?0:1;
}

Name: Anonymous 2006-11-09 20:27

PHP > Perl || python

Name: Anonymous 2006-11-09 21:20

>>6
That makes no sense, you should be using a bitwise OR, otherwise you are testing if PHP is greater than a boolean.

Name: Anonymous 2006-11-09 22:42

>>7
The string PHP is greater than any boolean.

Name: Anonymous 2006-11-10 2:07

>>7
Fail for not knowing order of operations.

>>6
Fail for making an always-true test.

Name: Anonymous 2006-11-10 8:03

>>9

PRECENDENCE

Name: Anonymous 2006-11-10 15:18 (sage)

>>10

What? '>' has higher precedence than '||', idiot.

Name: Anonymous 2006-11-10 21:54 (sage)

>>11

He was correcting >>9 for calling it "order of operations."

Dumb shit.

Name: Anonymous 2006-11-10 22:59

I haven't written java in years and I'm too lazy to compile/test this, but here goes:

public static boolean isprime( int x )
{
    int limit = Math.sqrt( x );
    for( int i = 2; i < limit; i++ )
    {
        if( x % i == 0 )
            return false;
    }
    return true;
}

I assume this is a homework assignment and it won't matter how fast this runs, so I did the easiest thing. If speed does matter, an easy way to make it faster would be to test if it's divisible by 2 first, then start the loop at 3 and increment by twos. You'll cut down on the number of divisions that way.

Name: Anonymous 2006-11-14 21:22

avja

Name: Anonymous 2009-01-14 13:35

WHBT

Name: Anonymous 2009-03-06 5:56

assume gnu date if.

Name: Anonymous 2009-03-06 7:44

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Name: Anonymous 2009-03-06 8:15


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Name: Anonymous 2011-02-04 16:20

Name: Anonymous 2011-02-17 19:47

dubz<

Name: Sgt.Kabu〵磰kiman䎴ꡈ 2012-05-28 21:03

Bringing /prog/ back to its people
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