BASH Unix Script problem

Hi guys and gals.

Could someone offer a little help to this annoying UNIX problem please? Ok, I gotta make a little script that jumps to a directory held in the environmental variables i.e


$ ./alsascript mypics 

would take me to $HOME/pics kinda thing. so i made this code:

#!/bin/bash
set -a
_webspace=$HOME/public_html/
_powerpoint=$HOME/public_html/pp
_databases=$HOME/public_html/
_spreadheets=$HOME/public_html/
set +a
      
if [ -z "$1" ];
    then echo argument is blank
else
eval cd $"$1" <<<<<<<<< ARGH!
echo New working directory is:
pwd

Now, when i run it from BASH and put say... ./alsascript powerpoint   it says "powerpoint" is not a directory. But if i change that line where i put ARGH! to eval cd $_powerpoint or any of the other variables it works so i assume the syntax on that line is wrong but i can't find anywhere what it should be. Any ideas to make it work?  Thank you in advance!

bash-2.05b$ _a=aaaaa
bash-2.05b$ m=_a
bash-2.05b$ eval echo \$"${m}"
aaaaa

how do you expect this to work anyway? by making this an actual script and not some function inside your .bashrc, you effectively start a new shell, tell it to cd to some dir and exit. the parent shell remains in the same directory you were in prior to launching the script.
why don't you just alias the directories? eg.
alias ppt="cd $HOME/public_html/pp"
reduces typing time.

Thanks, I'll give that a whirl.  I don't ever expect to use it, its for a rather dull assignment requested by our rather dull tutor to show we can make a Unix script which uses environmental variables.

lol what

quoting bold
still bold?