>>4
This troll's new math is for novelty purposes only. But just in case anybody takes his diploma from Tripplenigger-Anal Technical Academy seriously, I'll just explain why my original post in
>>2 is the correct answer here.
First off, 1,474,560 bytes DOES equal exactly 1440 KB, accounting for 1024 bytes per Kilobyte and that "KB" represents Kilobytes as opposed to Kibibytes ("KiB").
2 MB is the unformatted capacity of a dual-sided HD 3.5" floppy. 1,474,560 bytes is the maximum capacity when formatting a disk into 2880 sectors (18 sectors * 80 tracks * 2 sides) of 512 bytes per sector. On top of that, you have to consider the filesystem overhead, which leaves you with 1,457,664 bytes to work with, if using FAT12.
You can get more capacity (up to a theoretical 2 MB max on this same floppy disk type) by playing with the formula used to determine sector count. This is how DMF floppies work. You can also increase capacity by using a higher density disk formula, which is how larger "floppy" magnetic formats like 2.88 MB floppy, Zip disks, HiFD, and LS-120 floppiess work.
>>6
Base 8 vs. base 10 counting confusion isn't really the problem that the OP is experiencing. 1,457,664 by itself is not a significant number in base 10 at all. It's not significant in base 8 either until you realize that the FAT12 FS on the OP's disk requires 33 sectors (16,896 bytes) for itself.