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Chance computation... help

Name: Anonymous 2011-04-16 10:14

Say we have numbers 1 to 5 in randomized order, what is the chance of having at least two consecutive numbers that are adjacent to each other? Doesn't matter if it's ascending or descending...

Name: Anonymous 2011-04-17 1:24

40%

Name: Anonymous 2011-04-17 12:33

could you share the formula that you used?

Name: Anonymous 2011-04-21 17:12

hello.

Name: Anonymous 2011-04-22 5:33

5! = 120

Situations in where numbers can be consecutive/120

1 && 2, 2&&3, 3&&4, 4&&5 = 4 + other order = 8

8/120= 0.06666666666667

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