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Inequalities

Name: Anonymous 2010-06-17 4:36

Been a long time since I last took any kind of math class and I'm trying to solve some problems.

 *x/7-1<2x-1<2t-6x*

 *2x^2-9x+8>=0*
 
 *x^2-2x+1<0*

 *x^2+10x+25>=0*

I don't have any idea how to approach the first one. I assume i need to factor the other ones but I'm not really sure if that works. Any help would be appreciated.

Name: Anonymous 2010-06-17 9:42

I'm trying to solve some problems.

posts a bunch of inequalities

doesn't even say what the fuck he is trying to do

*facepalm*

Name: Anonymous 2010-06-17 14:07

I haven't yet gotten a good grasp of the math tags for /sci/ so I'm not going to use them at the risk of messing up.
x/7-1 < 2x-1 < 2t-6x
x/7 - 1 < 2x - 1
x/7 -1 (+1) < 2x -1 (+1) (add/sub of positive, no sign change)
x/7 (*7) < 2x (*7) (mult/div of positive, no sign change)
x (-14x) < 14x (-14x) (add/sub of negative, no sign change)
>-13x (/-13) < 0 (/-13) (mult/div of negative, sign change
x > 0
The solution for x is x > 0.

I can only solve for x, as I've never done multiple variable inequalities.  If I had to guess without looking:
2x - 1 < 2t - 6x
2x - 1 (-2x) < 2t - 6x (-2x)
-1 (/2) < 2t -8x (/2)
-1/2 (+4x) < t - 4x (+4x)
4x - 1/2 < t
which is t > 4x + 1/2.

Name: Anonymous 2010-06-17 14:10

>>3
Rats.  t > 4x - 1/2.

Name: Anonymous 2010-06-28 13:28

Name: Anonymous 2010-06-30 11:45

ME > YOU

Solve that one, Anon.

Name: Anonymous 2010-06-30 17:25

>>2
*facepalm*
Back to /b/, please

Name: Anonymous 2010-07-01 8:48

>>6
(YOU > ME) =/= (ME > YOU) It cannot, right?

therefore

(YOU > ME)  <  (ME > YOU) (the logic of this proof is proof)

:/

Name: Anonymous 2010-07-01 23:51

Ugh.  It's 2010 and we still have to talk about inequality.

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