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noko

Name: noko 2010-01-02 12:07

i have this stupid Chem packet that i need to finish today, so here's a question.

What is the volume of a sample of He (helium), that has a mass of 0.00173 g, given that the density is 0.178 g/L?  Convert your answer to mL.

Name: Anonymous 2010-01-02 14:45

Are you stupid or something?

Name: Anonymous 2010-01-03 5:28

>>2
He's from the imageboards, so obviously yes.

Name: Anonymous 2010-01-04 12:13

1) go in primary school
2) lrn2read
3) lrn2fractions
4) ?????
5) PROFIT !!!!!!

Name: Anonymous 2010-01-04 12:18

Name: Anonymous 2010-01-04 13:49

Oh, is this thread about noko?

Name: Anonymous 2010-01-04 13:57

I totally inhaled a couple of moles of helium this one time. I was speaking well funny

Name: 4tran 2010-01-04 19:43

>>7
inhaled a couple moles of helium
Is your lung capacity > 50L or something?

Name: Anonymous 2010-01-04 21:18

/frac{2}{3}

Name: Anonymous 2010-01-04 21:18

/frac{2}{3}

Name: Anonymous 2010-01-05 7:30

>>8
yes.

Name: Anonymous 2010-01-05 8:42

>>8
You just have to inhale really hard.

Name: Anonymous 2010-01-06 0:52

\lambda

Name: MD5 !SUUjOVb6Pg 2010-01-06 0:58

[math]F(X,Y,Z) = (X\wedge{Y}) \vee (\neg{X} \wedge{Z})[math]
[math]G(X,Y,Z) = (X\wedge{Z}) \vee (Y \wedge \neg{Z})[math]
[math]H(X,Y,Z) = X \oplus Y \oplus Z[math]
[math]I(X,Y,Z) = Y \oplus (X \vee \neg{Z})[math]

Name: MD5 !SUUjOVb6Pg 2010-01-06 1:00

yay for fail.

F(X,Y,Z) = (X\wedge{Y}) \vee (\neg{X} \wedge{Z})
G(X,Y,Z) = (X\wedge{Z}) \vee (Y \wedge \neg{Z})
H(X,Y,Z) = X \oplus Y \oplus Z
I(X,Y,Z) = Y \oplus (X \vee \neg{Z})

Name: Anonymous 2010-01-06 16:56

>>8
Not all at once!

Name: Anonymous 2010-01-09 17:22

0.00173 g He * 1 mole = x mole * 4 g

You have x = 0,0004325 moles of He. Under STP conditions that makes
x*22,4 L/mole = 0,009688 L

When we take the ratio of He mass and the resultant volume we get a density value of 0,178 g/L. That is equal to your expected value. So if you wonder the temperature that your helium at is 25 C degrees with 1 atm pressure.

Name: Anonymous 2010-01-10 20:47

[math]F(X,Y,Z) = (X\wedge{Y}) \vee (\neg{X} \wedge{Z})[\math]

Name: Anonymous 2010-09-11 19:31

bump

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