noko
1
Name:
noko
2010-01-02 12:07
i have this stupid Chem packet that i need to finish today, so here's a question.
What is the volume of a sample of He (helium), that has a mass of 0.00173 g, given that the density is 0.178 g/L? Convert your answer to mL.
2
Name:
Anonymous
2010-01-02 14:45
Are you stupid or something?
3
Name:
Anonymous
2010-01-03 5:28
>>2
He's from the imageboards, so obviously yes.
4
Name:
Anonymous
2010-01-04 12:13
1) go in primary school
2) lrn2read
3) lrn2fractions
4) ?????
5) PROFIT !!!!!!
5
Name:
Anonymous
2010-01-04 12:18
6
Name:
Anonymous
2010-01-04 13:49
Oh, is this thread about noko?
7
Name:
Anonymous
2010-01-04 13:57
I totally inhaled a couple of moles of helium this one time. I was speaking well funny
8
Name:
4tran
2010-01-04 19:43
>>7
inhaled a couple moles of helium
Is your lung capacity > 50L or something?
9
Name:
Anonymous
2010-01-04 21:18
/frac{2}{3}
10
Name:
Anonymous
2010-01-04 21:18
11
Name:
Anonymous
2010-01-05 7:30
12
Name:
Anonymous
2010-01-05 8:42
>>8
You just have to inhale really hard.
13
Name:
Anonymous
2010-01-06 0:52
\lambda
14
Name:
MD5
!SUUjOVb6Pg
2010-01-06 0:58
[math] F(X,Y,Z) = (X\wedge{Y}) \vee (\neg{X} \wedge{Z})[math]
[math] G(X,Y,Z) = (X\wedge{Z}) \vee (Y \wedge \neg{Z})[math]
[math] H(X,Y,Z) = X \oplus Y \oplus Z[math]
[math] I(X,Y,Z) = Y \oplus (X \vee \neg{Z})[math]
15
Name:
MD5
!SUUjOVb6Pg
2010-01-06 1:00
yay for fail.
F(X,Y,Z) = (X\wedge{Y}) \vee (\neg{X} \wedge{Z})
G(X,Y,Z) = (X\wedge{Z}) \vee (Y \wedge \neg{Z})
H(X,Y,Z) = X \oplus Y \oplus Z
I(X,Y,Z) = Y \oplus (X \vee \neg{Z})
16
Name:
Anonymous
2010-01-06 16:56
18
Name:
Anonymous
2010-01-09 17:22
0.00173 g He * 1 mole = x mole * 4 g
You have x = 0,0004325 moles of He. Under STP conditions that makes
x*22,4 L/mole = 0,009688 L
When we take the ratio of He mass and the resultant volume we get a density value of 0,178 g/L. That is equal to your expected value. So if you wonder the temperature that your helium at is 25 C degrees with 1 atm pressure.
19
Name:
Anonymous
2010-01-10 20:47
[math] F(X,Y,Z) = (X\wedge{Y}) \vee (\neg{X} \wedge{Z})[\math]
20
Name:
Anonymous
2010-09-11 19:31
bump
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