if f > g on T, then so are the integrals?

this has me confused right now. anyone have any tips on how to prove in general that

if f(x) > g(x) \forall x \in T, then

\int_T f\, dx > \int_T g\, dx

it seems obvious that it's true when you plot it and look at it and there's where my trouble is. how can i get past it being "obvious" and prove it?

>>4
Doh. You're right.

Now I'm thinking that it's not actually true but I'm having trouble producing a counterexample.