pi

with this formula

π = n sqrt {(sin 360 over n)^2 + (1 - cos 360 over n)^2} over 2

where n is the number of sides of a shape inscribed in a circle. it is correct to say that a n value of infinity will give a perfect mesurement of pi to infinte decimal places?

Why even bother with [sin(360) / n]^2 = [sin(0) / n]^2 = [0 / n]^2 = 0^2 = 0?

You sure your formula is correct?