Probability Question

You are given one pack of playing cards. No jokers.

Royal cards, K, Q & J's values are 0. Aces are valued at 1. The rest are at their face value.

You draw two cards. What is the probability of the two cards values added together being 11?

I can't think of a logical way to solve this. Can anyone help?

Well if they add up to 11, there's no royal cards involved.

So you either have
1+10
2+9
3+8
4+7
5+6
6+5
7+4
8+3
9+2
10+1

So you have 10 combinations there, but remember you have 4 choices for the first card (4 suits) and 4 for the second, so that's 10* 4*4 combinations.

Then divide that by the number of pairs of cards you can have (52*51).

Right?

>>2
Almost, but since the number of pairs of cards doesn't care about the order in which they're selected, it's actually 52 choose 2 = (52*51)/2

Yeah but I didn't divide by two when counting up the combinations.

5*4*4/26*51 = 10*4*4 / 52*51