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find the residue of

Name: Anonymous 2009-05-18 12:22

cos(z)/z^2 at the singularity z=0?

Name: Anonymous 2009-05-19 11:22

I get the larent series

z^-2 - 1 + z^2/4! - z^4/6! + ...

There's no z^-1 term though. Does that mean the residue is 0?

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