You mean the principle value of the argument?
Yes.
>>1 was stated badly, ignore it. I need to solve
>>4
I've almost got it
(1-i) = \sqrt2e^{-4/\pi}
Principle value is
ln(\sqrt2) {-i\pi/4}
So
|(1-i)^{2i-1}|=|e^{(ln(\sqrt2)-i\pi/4)(2i-1)} |
|(1-i)^{2i-1}|=|e^{(2iln\sqrt2 +\pi/2-ln\sqrt2+i\pi/4} |
Anyone know how to tidy up the last term so it's not in exponential form?