1 − 2 + 3 − 4 + · · · = 1/4

Prove me wrong.

>>38
 is >>26
except its well more put out

>>38
"this sums up to [(n/2)*(-1) + n] = -n/2 + 2n/2 = n/2"
it does not and this is not correct, in fact it is (-1)*(n-1)*(1/2) + n; take is we take m/2 that is an integer, then if n/2 doesnt belong to integer, the closest one that does is m = n - 1;
then it looks like (m/2)*(-1) + n = -m/2 + 2n/2 = (2n - m)/2 = (2n - n +1)/2 = (n+1)/2 and there, with either possibilties having equal possibilites we take the average value, which is
[(-n/2) + (n +1)/2]/2 = 1/2/2 = 1/4;
-n + n is 0, so wheres your point? how could it possibly give 1/4 ? :)

>>6


Maybe THINK about what the problem is saying instead of blindly applying some "test" that you learned in class whose proof you probably didn't even understand.

If you think this series diverges you're crazy. Every time a number is added a another number is subtracted. It has to balance out eventually (to 1/4), like the yin and yang.

>>43
lolitrollu.jpg

>>42
YHBT

>>29
"Habeeb it" is a formal proof.
Habeeb it.

>>46
I've thought about handing in a homework problem that gives a proof along the lines of:  "You wouldn't have asked the question if you didn't have a proof, therefore a proof exists, therefore the proposition is true. QED"