Name:
Anonymous
2009-05-03 21:05
the sum 1-2+3-4+... is equal to
\sum_{n = 1}^{\infty} [n*(-1)^{n+1}]
which is the same as
\sum_{n = 1}^{\infty} [(2n-1) - (2n)]
(expand it to verify it's the same series) but this reduces to
\sum_{n = 1}^{infty} (-1)
point made