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Name: Anonymous 2009-03-28 23:59

Does anyone know of any nice techniques for solving differential equations of the form p(x)x'' = k for x(t)?

Name: Anonymous 2009-03-29 1:10

Get out the old slide rule

Name: Anonymous 2009-03-29 3:34

Look up a numerical methods text for solving nonlinear differential equations, I've forgotten most of this unfortunately.

Name: 4tran 2009-03-29 3:43

x'' = k/p(x)

integrate both sides wrt x

integral( d(x')/dt , dx) = k integral(1/p(x) , dx)

hand wave the math to get

integral( (dx/dt) , d(x')) = k integral(1/p(x) , dx)
integral( x' , d(x')) = k integral(1/p(x) , dx)
(x'^2)/2 + C = k integral(1/p(x) , dx)

Solve 1st order diff eq, etc.

This is basically how one gets conservation of energy, etc

Name: Anonymous 2009-03-29 19:54

hand wave the math to get

lolwut

that doesn't seem right. proof plz

Name: Anonymous 2009-04-04 9:34

Bump for >>5

Name: 4tran 2009-04-04 12:10

slightly more rigorously
integral( d(x')/dt , dx)
integral( d(x')/dt , x' dt)
integral( x' d(x')/dt , dt)
x' * x' - integral(d(x')/dt  x', dt) + C (integrate by parts)

equating last 2 lines,
2integral( x' d(x')/dt , dt) = x'^2 + C
integral( x' d(x')/dt , dt) = (x'^2)/2 + C
as claimed, with integration constant since all integrals are indefinite

RHS doesn't change

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