Hard probability question...

When you leave the movie theater, an usher tells you that there were 175 girls and only 25 boys in the theatre.

A) This makes you wonder who was sitting in the row behind you (rows have 10 seats). Find the probability that the row behind was all girls, 9 girls exactly, 8 girls exactly 7 girls exactly, 6 girls exactly, and at least 6 girls.

So guys can you show me how to do 10 girls exactly and at least 6 girls. I can figure out the rest if i see how exactly this is solved.

lol u

Of course it's going to be assuming a number of things, but do not lawyerball math questions. It's the easiest way to piss off a teacher. you need to be able to determine the probablity of all girls, so, naturally you'll need to use the rule of multiplication.

All you do is find P(X) where x= 10 girls exactly.

So, you find the probability that the person at the end is a girl. That's 25/175 or 1/8. The chance of two girls being stationed together (statistically) is going to be 1/8*1/8 or 1/8^X where x is the # of girls in that row.

So, go ahead and just write the above and plug in the constant required.

Also: RTFM