Physics help?

A free particle has the initial wave function:

phi(x,0) = Ae^(-a|x|)

A and a are constants,

Normalise phi(x,0)

I got A = root a, but I doubt this is right somehow...

>>4
You're right! However, that way I don't get a good answer at all:
A^2 \left [ \int_{0}^{\infty}e^{-2ax}\,dx + \int_{0}^{\infty}e^{2ax}\,dx \right ] = A^2 \left [ -\frac{1}{2a} + \frac{1}{2a} \right ] = 1 ....?