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Physics help?

Name: Anonymous 2009-03-03 22:41

A free particle has the initial wave function:

phi(x,0) = Ae^(-a|x|)

A and a are constants,

Normalise phi(x,0)

I got A = root a, but I doubt this is right somehow...

Name: Anonymous 2009-03-04 10:58

Hmm, I'm not getting a real answer for A, since the wave function isn't complex:

Since phi(x,0) = Ae^{-a|x|}, P(x) = A^2 e^{-2a|x|}

Normalisation:
int_{0}^{inf} A^2 e^(-2a|x|) = \frac{A^2}{-2a} = 1 (integration is not evaluated from -inf to inf because of the absolute value of x)

Solving for A:
\frac{A^2}{-2a} = 1
A = \sqrt{\frac{1}{-2a}} -> nonreal value

I'm confuss. It's been a while though, I could be completely off :P

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