Return Styles: Pseud0ch, Terminal, Valhalla, NES, Geocities, Blue Moon. Entire thread

Calculus

Name: Anonymous 2009-02-26 21:24

I haven't done Calculus is 2 years.

Someone give me a Calculus problem to test me.

Name: Anonymous 2009-02-26 21:50

int(e^(x^2),x,a,b)

Name: Anonymous 2009-02-26 23:00

>>2
I'm not sure what to make of this. I'm not familiar with this notation.

Name: Anonymous 2009-02-26 23:23

Lim  X -> 5    1/5  =?

Name: Anonymous 2009-02-26 23:27

>>4
see wat u did there

Name: Anonymous 2009-02-27 0:18

you dont know integrals?

Name: Anonymous 2009-02-27 1:44

>>2
int(e^(x^2),x,a,b)
?

Name: Anonymous 2009-02-27 2:03

>>7
$$\int _a ^b {e^{x^{2}}}\,dx
% ?

Name: Anonymous 2009-02-27 2:06

$$\int _a ^b {e^{x^{2}}}\,dx$$

TEX is hard
:(

Name: Anonymous 2009-02-27 6:26

>>9
Preview your shit in at http://mathbin.net/ before you post.

Name: Anonymous 2009-02-27 11:30

\int_{a}^{b}dx

Name: Anonymous 2009-02-27 11:41

liek dis:

[m a t h]\int_a^b {e^{x^2}dx}[/ m a t h]


\int_a^b {e^{x^2}dx}

Name: Anonymous 2009-02-27 13:00

>>2
>>3

isnt that a cal3 problem?

Name: Anonymous 2009-02-27 15:55

>>13

umm... no that's an integration by parts problem. Typically taught in calc2. What the hell kind of backwards ass monkey college are you going to?

Name: Anonymous 2009-02-27 16:59

>>14

You can do \int_a^b {e^{x^2}dx} by parts? I'd like to see you try.

Name: Anonymous 2009-02-27 18:44

Name: Anonymous 2009-02-27 20:31

>>2

Either a troll or he meant (x^2)e^x, which can be done with integration by parts.

Solution to >>2:

http://integrals.wolfram.com/index.jsp?expr=exp(x^2)&random=false

Name: Anonymous 2009-02-28 0:55

>>17

How does one prove this integration by hand without using matlab? Is it really impossible?

Name: Anonymous 2009-02-28 1:19

>>18
derive the result of the integration.

Name: Anonymous 2009-02-28 6:06

>>18
Take a bite of peyote and contemplate it.

Name: Anonymous 2009-02-28 11:28

>>20
Suddenly math's fun!

Name: Anonymous 2009-02-28 17:59

>>18

You can do it if you know the definition of the erf function, shown here: http://mathworld.wolfram.com/Erf.html


Apply the fundamental theorem of calculus to get the derivative of erf, use the defintion of erfi:

erfi = -i*erf(i*z)

This should give you a means to integrate it.

Name: Anonymous 2009-03-01 16:14

>>22

That's too damn advanced for my little pea brain. Which graduate class do you have to take to learn about the erf function?

Name: Anonymous 2009-03-01 17:38

>>23
Calculus 4↑↑8

Name: Anonymous 2009-03-01 17:42

>>23

Junior-level engineering, lol.

Name: Anonymous 2009-03-01 17:45

>>25 again

To be more specific, we used the erf function in solving heat transfer partial differential equations in spherical coordinates in our heat & mass transfer class in our 3rd year of chemical engineering.

Name: Anonymous 2009-03-01 20:38

>>23
As an answer to the question posed it's hardly advanced.

The error function is pretty much just defined as the solution to the integral you were given (well with a few sign changes, that are easily worked around). You've just defined away your problem.

Name: Anonymous 2009-03-02 16:46

>>23
Here.

You guys were right it's actually not that hard. I just glanced at it for a second and didn't even bother to understand it.

Name: Anonymous 2009-03-03 14:54

<a href="http://www.buyaionmoney.com">aion kina</a>
<a href="http://www.buyaionmoney.com">aion gold</a>
<a href="http://www.aiongold-money.com">aion gold</a>
<a href="http://www.aiongold-money.com">aion money</a>
<a href="http://www.aiongold-aiongold.com">aion kina</a>
<a href="http://www.aiongold-aiongold.com">aion gold</a>
<a href="http://www.rs2accounts-rs2accounts.com">runescape gold</a>
<a href="http://www.rs2accounts-rs2accounts.com">runescape money</a>
<a href="http://www.aionkina-aionkina.com">aion kina</a>
<a href="http://www.aionkina-aionkina.com">aion gold</a>
<a href="http://www.benniuw.com">股票软件</a>
<a href="http://www.benniuw.com">股票分析软件</a>

Name: JimiHendrix !qHyjmd9XCE 2009-03-03 21:22

I have a problem with this one:
Find the derivative of the function:
{2^{3^{x^{2}}}}
It's answer is supposed to be something like this:
{2^{3^{x^{2}}}}(ln 2)(\frac{d}{dx}({3^{x^{2}}})})
I think I have to use the chain rule, but if that's true why does this:
{2^{3^{x^{2}}}}}{(ln 2)(\frac{d}{dx}({3^{x^{2}}})})
stay the same?
Shouldn't it be:
{2^{3^{2x}}} or {6^{2^{x^{2}}}}
Could someone help me?
Please.

Name: JimiHendrix !qHyjmd9XCE 2009-03-03 21:32

Sorry about that ^
This is what it's supposed to say.

It's answer is supposed to be something like this:
{2^{3^{x^{2}}}(ln 2)(\frac{d}{dx}({3^{x^{2}}})})
I think I have to use the chain rule, but if that's true why does this:
{2^{3^{x^{2}}}}(ln2)(\frac{d}{dx}(3^{x^{2}}))
stay the same?

Name: Anonymous 2009-03-03 21:40

See the first item under "Derivatives of Exponential and Logarithmic Functions" at http://en.wikipedia.org/wiki/Table_of_derivatives.

So you'd have (2^(3^(x^2)))*(3^(x^2))*ln(2)*ln(3)*2x for the final answer.

Name: Anonymous 2009-03-04 21:32

Integrate x^x^x from a to b.

Newer Posts
Don't change these.
Name: Email:
Entire Thread Thread List