e

Hey /sci/,

In a problem I'm doing I've got e^(1/2 ln|x^2+1|). Somehow this becomes sqrt(x^2+1).

My guess is that when you have e^(ab) you get (e^b)^a, which in this case where a = 1/2 and b = ln|x^2+1|, you get e^ln|x^2+1| = (x^2+1)^1/2 = sqrt(x^2+1). I don't understand why this would happen though.

Can someone please explain why this happens, or at least tell me if I'm right in my guess that e^(ab) = (e^b)^a?

tell me if I'm right in my guess that e^(ab) = (e^b)^a?

no.

http://www.google.com/search?q=properties+of+logs

>>2
OOOOH NIGGA SHOWED YOU
JUST GOTTA PUT THAT 1/2 IN THAT LOG.
JUST FUCKIN' MAKE THAT THE EXPONENT OF THE INSIDE, MOTHERFUCKER.
SHITS LIKE E TO THE FUCKING NATURAL LOG OF THE SQUARE ROOT OF X SQUARED PLUS
FUCKING SHIT.

oh hmm this looks very easy actrually