Vip quality exercise

So folks, How this come to be solved?

Graphically represent the points of the plane that verify:

a) 3x+4y>12 ^ 3x+4y>0
b) 3x+4y>12 v 3x+4y>0

Lol i know how to do it individually but I do not know what "^" and "v" means.

me neither.

"^" means "and"

"v" means "or"

So part a is just asking for the overlap (intersection) of the two regions, and b is asking for the union.

3 is right. a is asking for the intersection of the two inequalities (the region of the plane which contains points from both inequalities) and b is asking for the union of the two inequalities (the region of the plane which contains points from either inequality)

>>4
Wow, way to say the exact same thing as >>3 but in ten times as many words.

>>5
That's what the mathematics is all about!

zing! take that, math

Hi folks, Op here with an related question:
I have this data:

A(-1,-6) B(-1,1)

And I need the equation of the AB line, and I try to get it by the "equation of a straight Line from two points":

y-y1=[(y2-y1)%(x2-x1)](x-x1)

So:

y+6=[(1+6)%(-1+1)](x+1)

But (1+6)%(-1+1) is 7/0 and x/0 does not exist.
That's cool because the slope is straight up and it isn't supposed to exist.
But how do I get the full-powered Line Equation from that? I can't multiply things with nothing. LOL

>>8
Doesn't the line x = -1 intersect both those points?

>>9
Is that a question?  Are you unsure?

>>10
I'm pretty sure, but I'm asking the question to get him thinking.

>>9

Lol ok, but my equation should look like this:
y=mx+n
and you gave me this:
x=WTF

lol wut