Name:
Anonymous
2009-01-07 5:41
lim as x->1 of 1/(x+3) is 1/4.
Name:
Anonymous
2009-01-07 19:21
Let \epsilon > 0 and let \delta = 16\epsilon. Then
\left|\frac{1}{(1+\delta)+3} - \frac{1}{4}\right| = \left|\frac{\delta}{4(4+\delta)}\right| < \frac{\delta}{16} = \epsilon