Name: Anonymous 2009-01-03 6:35
Let S = { \frac{x-2}{x+3} \mid x \in \Re, x \geq 0 }
Prove that Sup(S) = 1 and Inf(S) = -\frac{2}{3}
It's easy to see it's true but how to prove it fairly rigorously?
Prove that Sup(S) = 1 and Inf(S) = -\frac{2}{3}
It's easy to see it's true but how to prove it fairly rigorously?