In coordinate geometry:
Given the midpoints of the sides of a triangle: P(2,5), Q(4,2) and R(1,1)
Find the coordinates of the vertices.
And tell me how you solved it.
Name:
Anonymous2008-11-26 9:12
Find the line parallel to PQ that passes through R, then the same for the others points and lastly find the intersections of the lines.
Name:
Anonymous2008-11-27 8:01
HURR DURR.
if they are midpoint of triangle, then the resultant triangle from the midpoints would bisect perpendicularly to the original triangle. go from there fag00.
Midpoint between 2 points (X1,Y1) and (X2,Y2) is ((X1+X2)/2,(Y1+Y2)/2).
I'd make 3 points (X1,Y1),(X2,Y2),(X3,Y3) and then you can create a system of equations that you can easily solve.
Name:
Anonymous2008-11-30 20:13
Greetings anon, on this wonderful evening. >>1 through >>6 are completely Phail. To solve this, one needs to simply use vectors and the parallelogram rule, i.e., let a,b and c represent the vertices of the larger triangle.
Thus, b = \stackrel{\rightarrow}{RP} + \stackrel{\rightarrow}{RQ}, c = \stackrel{\rightarrow}{PR} + \stackrel{\rightarrow}{PQ} and a = \stackrel{\rightarrow}{QR} + \stackrel{\rightarrow}{QP}.
Name:
Anonymous2008-11-30 20:18
Fuck me.
b = \vec{RP} + \vec{RQ}, c = \vec{PR} + \vec{PQ} and a = \vec{QP} + \vec{QR}.