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1
Name:
Anonymous
2008-11-04 17:35
just a quick one guys
how do i show for all vectors a,b,c that
(AxB)x(AxC)=[(AxB).C]A
4
Name:
4tran
2008-11-04 23:46
(δ
jm
δ
kn
ε
pqj
A
m
A
p
B
n
C
q
) - (δ
jn
δ
km
ε
pqj
A
m
A
p
B
n
C
q
) =
(ε
pqm
A
m
A
p
B
k
C
q
) - (ε
pqn
A
k
A
p
B
n
C
q
) =
({ε
pqm
A
p
C
q
}A
m
B
k
) - ({ε
pqn
A
p
C
q
}B
n
A
k
) =
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