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Precalc bonuses

Name: Anonymous 2008-10-15 14:36

hey /sci/, first time poster, here's an interesting set of questions

not my homework, just some bonuses on my last precalculus test i was intrigued by.

first is (oh and x^y means x to the y power);
what do you get when you divide x^74-5x^60+x^23+x^6 by x-2?

this one i'm stumped on, you would have to write out all the intermediate x values with a zero coefficient, right?


last one was: write a polynomial with the roots (4, 5, i2). I know the 4 and 5 would be (x-5) and (x-4), but what about that i2? how would you work BACKWARDS through the quadratic formula?

Name: Anonymous 2008-10-15 16:08

1. Polynomial division. Use it. Also zero coefficient = nothing at all. Idiot.
2. (x-5)(x-4)(x-2i)(x+2i)
Quadratic formula backwards? WTF are you talking about?

lern2math

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