Math :(

I'm having trouble with this Math problem.

"Divide the first triangular number by 3 and record the remained. Divide the second triangular number by 3 and record the remainder. Repeat this several more times. Do you notice a pattern? What is the pattern?"

I swear, this is almost Chinese to me, I can't understand it. Can anyone help me out?

http://en.wikipedia.org/wiki/Triangular_numbers

http://en.wikipedia.org/wiki/Remainder

So, something like this then?

n(n + 1) / 3 where n = 1?

And then n(n + 1) / 3 where n = 3?

So on and so forth for 6, 10, etc.?

no, triangular number is \frac{n(n+1)}{2}

so it would be

\frac{\frac{n(n+1)}{2}}{3} when n=1
\frac{\frac{n(n+1)}{2}}{3} when n=2
\frac{\frac{n(n+1)}{2}}{3} when n=3
...

the numbers 1,3,6,10,15,\ldots are is the solutions to \frac{n(n+1)}{2} for n=1,2,3,4,5,\ldots. so you need to find the remainders of

\frac{1}{3}
\frac{3}{3}
\frac{6}{3}
\frac{10}{3}
\frac{15}{3}
...

I understand now. Thank you for your help, kind anon.

>>1
Can't be done. You're black.

3 divided by 3 is 1.  God you guys are dumb.