Math

Whats y´ of y=x^2/x+1

>>42 Yes, you can't divide by zero.
So what if the "singularity" is "removable" (Please define both), f=x^2/x is still not defined in zero, thus is not continuous in 0.
In conclusion. If g(x)=x, then f!=g. BUT f ∪ {(0,0)} = g