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Name: Anonymous 2008-03-26 17:34

Integrate sqrt(16-x^2).

Name: Anonymous 2008-03-26 17:36

>>1
sqrt(16-x^2) = 0

ergo your wrong bitch

Name: Anonymous 2008-03-26 18:27

>>2
It's not so, unless x is -4 or 4.
What about in between -4 and 4?

Name: Anonymous 2008-03-26 19:22

1/2 * x * sqrt(16-x^2) + 8 * arcsin(x/4)

gb2/integrationbytrigonometricsubstitution101/

Name: Anonymous 2008-03-26 20:07

>>2
This may surpise you, but I invented that meme.
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