int 1/(2 + e^x) dx

I can't figure out how to get the result (x - log(2 + e^x))/2 + C. It looks like integration by parts, it also looks similar to the integral of log(x), x(log(x) - 1) + C but I'm still completely lost. Should partial fractions be used?

int 1/(2 + e^x) dx
That has got to be the worlds most difficult intelligence check ever.