>>6
how about this?
the set is
{nothing,bread,ham,egg,...}x
{nothing,bread,ham,egg,...}x
{nothing,bread,ham,egg,...}x...
whence the group action take off ham acts in bread =
(bread,nothing,nothing,...) as the identity operator? i.e
(bread,nothing,nothing,...)->(bread,nothing,nothing,...)
as I recall this just leaves the action not free, plz correct if
i'm wrong, ty