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e^(pi * i) + 1 = 0

Name: Anonymous 2007-12-13 5:18

Why? I don't understand this at all ><

Name: Anonymous 2007-12-20 8:47

a really, really bad proof (but i don't have the time for anything more fancy):
z=cos(x)+i*sin(x)
dz/dx=-sin(x)+i*cos(x)=i*(cos(x)+i*sin(x))=i*z
dz/z=i*dx
ln(z)=ix + c
z=C*exp(ix)

bad one i know

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