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!!! CALCULUS!!! ><

Name: Anonymous 2007-12-06 19:20

lol coming to 4chan... the internet hate machine is definately my last resort... but please some one HELP ME WITH THIS CALCULUS PROBLEMMM AHHHHHH

THE POWER LEVEL OF THIS EQUATION IS OVER 9000!!!!

I CAN'T FIND THE INDEFINITE INTEGRAL OF THIS EQ.

         ...(1-(x)^(1/2))/(1+x^(1/2))

I tried substitution but my equation got only more complicated....

some anonymous mathmeticians/scientists.... one please help... thanks

Name: Anonymous 2007-12-06 19:51

>>3
I am asking for the indefinate integral... you have failed. >:[[]]

okay anyways seriously...

I have managed to progress further by manipulating the substitution equation...
u=1 + x^(1/2)
and resulted with
u - 1 = x^(1/2)

When I sub in u-1 for x^(1/2) 
I get (2 - u) / u

Integrating this I get 2ln(u) - u and even after substituting u =
1+x^(1/2) I still don't get the text book's answer

 (5 + 4(x)^(1/2) - x - 4ln(1+ (x)^(1/2)) + C) but this instead...

2ln(1+ (x)^(1/2)) + 1+ (x)^(1/2)

Please help me anonymous mathmeticians/scientists


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