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Name: Anonymous 2007-11-24 17:52

|log 2 (3x-1/3)|=|log 2 (5-2x/2)|
How does one go about solving such an equation?

Name: Anonymous 2007-11-24 18:39

It's practically the same answer, no?

2^|log 2 (3x-1/3)| = 2^|log 2 (5-2x/2)|
3x-1/3 = 5-2x/2
etc.

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