So I am in BC Calc in my high school and we started rotations of functions. Now, the way i see it, a cylinder should be able to be evaluated to a rectangular prism, with r=l, and h=h, and then seeing as a full rotation is 2PI w=2PI. But it doesn't work for the rectangle. Can Anyone tell me where I've gone wrong?
Name:
Anonymous2007-11-21 5:20
Ummm... wot?
Let's see:
calculus and rotations of functions
cylinder and rectangular prism
r = 1
h = h
2πw = 2π
???
Don't know what your saying but I'll go ahead and show you how to find the volume of a cylinder with:
calculus and rotations of functions
a rectangle
radius = 1
height = h
Firstly, the volume of integration of function f(x) between a and b rotated around the x-axis: V = π∫(y)2dx,a,b
OK now then. To find your volume i'm going to rotate f(x)=h around the y-axis between 0 and 1.
Here's a crappy diagram (WARNING CRAPPY DIAGRAM IS CRAPPY): ,,,,,,,___,,,,,,..
,,,,,--,[b]|[/b],--,,,,..
,,,,/,,,[b]|___[/b]\,,,<h
,,,,\,,,[b]|[/b],,,[b]|[/b],,,..
,,,,|--_[b]|[/b]_--[b]|[/b],,,..
,,,,|,,,[b]|[/b],,,[b]|[/b],,,..
,,,,|,,,[b]|[/b],,,[b]|[/b],,,..
,[b]--------------[/b],<0
,,,,\,,,|,,,/,,,..
,,,,,--___--,,,,..
,,,,,,,,,,,,,,,,..
........^...^...
........0...1...
The axis and rectangle we will rotate are bold.
Now the volume we want to find is (since this is around the y-axis we swap the y to x, dx to dy and the a and b values to 0 and h):
V = π∫(x)2dy,0,h
Since the x value is 1 throughout, x=1
V = π∫(1)2dy,0,h
V = π∫1dy,0,h
V = π[y],0,h
V = π(h - 0)
V = πh
Working out the volume of a cylinder with radius = 1 and height = h normally to make sure it's correct:
V = πr2h
V = π×12h
V = π×1×h
V = πh