>>14 here.
>>15
The initial assumption in
>>6 isn't that .999...=1. It's that x = .999 (which we are allowed to define as true). From there, we use operations that keep the original equation intact, until we come to 9x = 9. We divide both sides by 9, and viola! .999...=x=9/9=1. lrn2math, fool.