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0.999... = 1

Name: Anonymous 2007-11-17 12:16

Oh snap!

Name: Anonymous 2007-11-18 22:41

>>16
The basic definition of convergence of a sequence over a metric space (in this case, R with d(x,y)=|x-y| is given by:

{x_n} is said to converge to x iff for every epsilon > 0, there exists an natural number N such that for all n > N, d(x, x_n) < epsilon.

Basically you take x_1 = 0.9, x_n = x_(n-1) + 9/10^n as your sequence, which clearly becomes 0.999... as n approaches infinity and show that it converges to 1.

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