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metric space topology

Name: Anonymous 2007-11-09 20:17

halp, how do I show that the set of bounded functions under the supremum norm is a complete metric space?

Name: Anonymous 2007-11-11 19:01

>>7

There's also a sense that proof by contradiction, used where you don't need it, is less "positive" than one achieved by other means. What I mean is, by proving something directly using what properties we can derive, we're understanding more precisely WHY the theorem holds. A proof by contradiction might give us some idea, but it's not a full understanding, it doesn't teach us as much about what we're working with.

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