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complex numbers

Name: Anonymous 2007-10-31 19:26

Find the roots of the equation (z+1)^3 = 1, in the form x+iy.

gogogo

Name: anon 2007-11-01 21:41

(x+1)^3 = (x+1)(x^2+2x+1) = x^3+2x^2+x+x^2+2x+1 = x^3+3x^2+3x+1

Problem: roots of (x^3+3x^2+3x = 0)

x(x^2+3x+3) = 0 (<--This makes zero one of the roots)

Roots of (x^2+3x+3):
[-3+/-sqrt(9-4(1)(3))]/2 (<--Quadratic Formula)
-1.5+i*sqrt(3/4) and -1.5-i*sqrt(3/4) (<--I solved it in my head to the form of (a+bi) like complex numbers are supposed to be written.)

There.  Turn that in and prove that you don't understand it.

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