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complex numbers

Name: Anonymous 2007-10-31 19:26

Find the roots of the equation (z+1)^3 = 1, in the form x+iy.

gogogo

Name: Anonymous 2007-11-12 15:27

>>47
Then reduce for me the following:

(4+6i)/(8+10i)

Surely, this can be put into some kind of a+bi form, without remaining a quotient, right?

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