complex numbers

Find the roots of the equation (z+1)^3 = 1, in the form x+iy.

gogogo

>>10
No, it means:
(x+1)^3 = 1 -> x+1 is a third root of 1. Therefore x+1 = 1, (-1 + i*sqrt(3))/2, or (-1 - i*sqrt(3))/2. Therefore x = 0, (-3 + i*sqrt(3))/2, or (-3 - i*sqrt(3))/2.