Let x = 0.999... (given)
10x = 9.999... (multiply both sides by ten)
9x-x = 9.999...-x (subtract x from both sides)
9x-x = 9.999...-0.999... (substitute 0.999... for x on right)
9x = 9 (combine like terms)
x = 9/9 (divide both sides by 9)
x = 1 (simplify the fraction)
0.999... = 1 (substitute 0.999... for x on left)
why come do I divide 9/9, it never show 0.999...
Because it ass lick way to show answer.
Name:
Anonymous2007-11-05 8:55
0.666... does indeed equal 1. In base 7
Name:
Anonymous2007-11-07 14:59
0.9... = 1 - 0.0...1
Name:
Anonymous2007-11-07 15:59
>>30
You're correct in that you're wrong in a good way. Being that .0...1 doesn't really mean anything but zero, you pretty much wrote that 1=1-0. However, your implication of infinitesimals is, of course, stupid and a failed troll.
This whole topic fails at life.
Name:
Anonymous2007-11-07 20:26
>>31
Actually, he's wrong in a wrong way. 0.0...1 is meaningless in ways that 0.9... isn't. There's can't be a last digit (1 or anything else) if there is an infinite number of digits preceding it.