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Try some physics.

Name: Anonymous 2007-09-30 20:13 ID:RqeuzhK8

Pitcher's mounds are raised to compensate for the verical drop of the ball as it travels 18m to the catcher. (a) If a pitch is thrown horizontally with an initial speed of 32 m/s, how far does it drop by the time it reaches the catcher? (b) If the speed of the pitch is increased, does the drop distrace increase, decrease, or stay the same? Explain. (c) If this baseball game were to be played on the Moon, would the drop distance increase, decrease, or stay the same? Explain.


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Astronomers have discovered several volcanoes on Io, a moon of Jupiter. One of them, named Loki, ejects lava to a maximum height of 2.00 x 10^5 m. (a) What is the initial speed of the lava? (The acceleration of gravity on Io is 1.80 m/s^2.) (b) If this volcano were on Earth, would the maximum height of the ejected lava be greater, less than, or the same as on Io? Explain.

Name: Anonymous 2007-09-30 21:11 ID:Heaven

wow this is a really fascinating problem

Name: Anonymous 2007-09-30 21:39 ID:U2D7eKuq

Try posting your homework problems online and seeing what idiots will answer them for you! Oh wait...

Name: Anonymous 2007-09-30 22:00 ID:+TUDOuh5

>>1
a) You have to use the normal distribution: F(x) = (32m/s)2/3, A = 18 - F(1/32) - F(0) = 5m
b) The drop distance will actually increase, since air friction rises with the square of the speed, and slows the ball down.
c) The drop distance would stay the same, as the moons increased curvature will compensate for the lower gravity.

a) Here you use the SUV-AT equations. The lava must be going very fast, but your average SUV can't go faster than 110 mph (and then it'll topple in no time), so probably around there.
b) Here we have to compare IO speed to Earth. Now IO speed on Earth is measured in Terrabytes, which is very fast, most IO speeds are much less than that so the height will also greater on earth.

Name: 4tran 2007-10-01 0:44 ID:Heaven

>>4
I lol'd

Name: Anonymous 2007-10-05 20:52

>>4
one internet for u

Name: Anonymous 2007-10-06 13:14

b/c, decrease, I'm too lazy to explain, and calculate a

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