Math question

Hey I have question and I bet you can solve it.
Some people are going to fire off a rocket and they want to know the height of it. They want to create a program using a math formula that will help them do this.
They will have 3 angles equaling 180 and they will also have the distance from a point and the rocket.
I don't know what formula they could use to do this and I was hoping you could help.

Sounds like a trig problem - a diagram showing what you know and where it fits would help.

Ok then.

You have a triangle and you are 450ft away from the point of take off. You know that one angle is 90 degrees and lets just say the other 2 are 60 and 30.

  |\
X | \ Y
  |  \
  |   \
  |____\
450


 |\
 | \
a|  \ c
 |   \
 |___t\
   b
You know b, the distance from the rocket, and t, the angle to the tip of the rocket. You want to find a, the height of the rocket.

a/b = tan(t).

Solve for a. Don't know why I am helping you. You should be able to figure this out yourself easily.

So if a/b=tan(t) and t=60 and b=450
a/450=.32 (rounding)
a=450x.32
a=144ft

>>5
No. tan(60 degrees) = tan(pi/3 radians) = sqrt(3) = 1.732. Set your calculator to degrees or convert to radians yourself. If the angle is 60 degrees, notice that a looks so much bigger than b.

Also you should memorize this. If the angle is t, then
sin(t) = a/c         opposite over hypotenuse
cos(t) = b/c         adjacent over hypotenuse
tan(t) = a/b         opposite over adjacent

Some old hippie caught a high tripping on acid

sohcahtoa

^
[S]ine
[O]pposite
[H]ypotenuse
[C]osine
[A]djacent
[H]ypotenuse
[T]an
[O]pposite
[A]djacent
For anyone that can't figure out the above.
If the rocket travels close to vertically before reaching the maximum height, the triangle there should do fine. If there's considerable curving or deflection, you're going to need more triangles.

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