I destroy your brain now k?
Name:
Anonymous
2007-09-16 14:24
ID:vjLtBMtB
Suck on this
a=b
a^2=ab
a^2-b^2=ab-b2
(a-b)(a-b)=b(a-b)
a-b=b
b+b=b
2b=b
2=1
brain = ruined
Name:
Anonymous
2007-09-16 15:16
ID:HB62oNy2
Congratulations, you are working in the trivial ring. In this ring everything equals 0, hence you can divide by it.
Otherwise you have made a mistake on this step:
(a-b)(a-b)=b(a-b)
a-b=b
You can only divide by zero in the trivial ring.
Name:
Anonymous
2007-09-16 15:45
ID:DTitI1km
a^2-b^2 does not factor into (a-b)(a-b)
(a-b)(a-b)=a^2-2ab+b^2
Name:
Anonymous
2007-09-17 6:43
ID:Heaven
Not to mention if a^2=ab then a=b to begin with.
Name:
Anonymous
2007-09-17 11:30
ID:z4kmZnsW
(a-b)(a-b)=b(a-b)
a-b=b
Huh.
Name:
Anonymous
2007-09-17 22:41
ID:x5a6X3me
a=b
a^2=ab
a^2-b^2=ab-b2
(a-b)(a+b)=b(a-b)
(a+b)=b
a=b-b
a=0=b
(a+b)(a-b)= a^2-ab+ab-b^2 = a^2-b^2
(a-b)(a-b)= a^2+2ab+b^2
In this situation where a=b=0
a^2+2ab+b^2 = a^2-b^2 but only because they both = 0.
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