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Any tutors on at this late hour?

Name: Anonymous 2007-09-07 6:56 ID:aUWkAQYB

Alright, I hope you guys don't mind me asking this but I literally have nowhere else to look.

I've always been horrible with integrals.

The problem is ∫ 1/(t^2)sqrt(25+t^2) dt

I substituted 5tanӨ for x so now I have

∫ 1/(tan^2(Ө))sqrt(25+25tan^2(Ө)) * 5/cosӨ dӨ

I manage to turn this into

∫ secӨ/25+tan(Ө) dӨ

But I am now absolutely stumped at how I should proceed. I have the integrals of both of the expressions, but it looks like this isn't an f'(x)/f(x) situation, so that destroyed whatever help my book or notes could give me on this.

Name: Anonymous 2007-09-07 12:10 ID:nt7zK/bf

>>1
Do you mean
∫ 1/((t^2)sqrt(25+t^2)) dt
or
∫ (1/(t^2))(sqrt(25+t^2)) dt

?

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