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Diff. Eq.

Name: Anonymous 2007-09-02 10:03 ID:D6QdaoP5

I'm at a loss about how to solve the following differential equation:

x'' = x^0.25

That is, double derivative of x equals x to the 0.25th power.

It's very frustrating because I have a feeling it's very trivial. Can anybody help, please? Thanks.

Name: Anonymous 2007-09-02 22:15 ID:Heaven

DSolve[y''[x]-y[x]^(1/4)== 0,y[x],x] Actually

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