Diff. Eq.

I'm at a loss about how to solve the following differential equation:

x'' = x^0.25

That is, double derivative of x equals x to the 0.25th power.

It's very frustrating because I have a feeling it's very trivial. Can anybody help, please? Thanks.

>>22

No. x is a function which depends on a variable, t in this case.

To check a solution, you take its expression (such as "c1*sin(t)+c2*cos(t)") and substitute x by that. Then you substitute x' by its first derivative ("c1*cos(t)-c2*sin(t)" in this example). Then x'' by its second derivative ("-c1*sin(t)-c2*cos(t)" in this example).