Diff. Eq.

I'm at a loss about how to solve the following differential equation:

x'' = x^0.25

That is, double derivative of x equals x to the 0.25th power.

It's very frustrating because I have a feeling it's very trivial. Can anybody help, please? Thanks.

>>16

no. let u = x^(1/8), differentiate through by x and you'll get a du/dx

(1/3)(u)^3 --diff--> (du/dx)^3

u = x^(1/8)
du/dx = (1/8) x^(-7/8)

substitute it in.