You should be able to solve this.

x - 7 = 19 + x

A famous meme on /b/, well, I just solved it and want the credit.

x-x=26

(x^2)^0.5= a + and - number
For example. -3*-3=9, 3*3=9, therefore 9^0.5 = -3 and 3

+x--x=2x
x-x=26
2x=26
x=+13 and -13

You know, if you just define
"x - 7 = 19 + x

A famous meme on /b/, well, I just solved it and want the credit.

x-x=26

(x^2)^0.5= a + and - number
For example. -3*-3=9, 3*3=9, therefore 9^0.5 = -3 and 3

+x--x=2x
x-x=26
2x=26
x=+13 and -13"
to stand for
"I am the weakest, most transparent troll on the planet, and yet I somehow succeed.", >>1 makes perfect sense.

Well done, >>1, well done. You certainly proved something.

>>33
You can't define a set as 'positive on the left and negative on the right'. The set is an abstract entity, the left/right/equal sign thing is just notation. You'd get stuff like x = 5, but 5 != x.
And basic operations like moving terms from one side of the equation to the other assumes that "x + 1 = x + 1"
And if you redefine x = x to mean x = -x, then x = x -> x = 0, which as >>35 says works out poorly for integer constants not 0.